1/4(8z-4)=z+8-2z

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Solution for 1/4(8z-4)=z+8-2z equation: 



1/4(8z-4)=z+8-2z

We move all terms to the left:

1/4(8z-4)-(z+8-2z)=0



Domain of the equation: 4(8z-4)!=0

z∈R



We add all the numbers together, and all the variables

1/4(8z-4)-(-1z+8)=0

We get rid of parentheses

1/4(8z-4)+1z-8=0

We multiply all the terms by the denominator


1z*4(8z-4)-8*4(8z-4)+1=0

Wy multiply elements

4z^2(8-32z(8+1=0

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