1/4(8z-4)=z+8-2z

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Solution for 1/4(8z-4)=z+8-2z equation:



1/4(8z-4)=z+8-2z
We move all terms to the left:
1/4(8z-4)-(z+8-2z)=0
Domain of the equation: 4(8z-4)!=0
z∈R
We add all the numbers together, and all the variables
1/4(8z-4)-(-1z+8)=0
We get rid of parentheses
1/4(8z-4)+1z-8=0
We multiply all the terms by the denominator
1z*4(8z-4)-8*4(8z-4)+1=0
Wy multiply elements
4z^2(8-32z(8+1=0

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