1/4(X+2)=1/3(2x+6)

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Solution for 1/4(X+2)=1/3(2x+6) equation: 



1/4(X+2)=1/3(2X+6)

We move all terms to the left:

1/4(X+2)-(1/3(2X+6))=0



Domain of the equation: 4(X+2)!=0

X∈R





Domain of the equation: 3(2X+6))!=0

X∈R



We calculate fractions


(3X2/(4(X+2)*3(2X+6)))+(-4XX/(4(X+2)*3(2X+6)))=0



We calculate terms in parentheses: +(3X2/(4(X+2)*3(2X+6))), so:

3X2/(4(X+2)*3(2X+6))

We multiply all the terms by the denominator


3X2

We add all the numbers together, and all the variables

3X^2

Back to the equation:

+(3X^2)





We calculate terms in parentheses: +(-4XX/(4(X+2)*3(2X+6))), so:

-4XX/(4(X+2)*3(2X+6))

We multiply all the terms by the denominator


-4XX

Back to the equation:

+(-4XX)



We get rid of parentheses

3X^2-4XX=0

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