1/4(a+4)=1/3(a+5)

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Solution for 1/4(a+4)=1/3(a+5) equation: 



1/4(a+4)=1/3(a+5)

We move all terms to the left:

1/4(a+4)-(1/3(a+5))=0



Domain of the equation: 4(a+4)!=0

a∈R





Domain of the equation: 3(a+5))!=0

a∈R



We calculate fractions


(3aa/(4(a+4)*3(a+5)))+(-4aa/(4(a+4)*3(a+5)))=0



We calculate terms in parentheses: +(3aa/(4(a+4)*3(a+5))), so:

3aa/(4(a+4)*3(a+5))

We multiply all the terms by the denominator


3aa

Back to the equation:

+(3aa)





We calculate terms in parentheses: +(-4aa/(4(a+4)*3(a+5))), so:

-4aa/(4(a+4)*3(a+5))

We multiply all the terms by the denominator


-4aa

Back to the equation:

+(-4aa)



We get rid of parentheses

3aa-4aa=0

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