1/4(a+5)=1/2(6+a)

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Solution for 1/4(a+5)=1/2(6+a) equation: 



1/4(a+5)=1/2(6+a)

We move all terms to the left:

1/4(a+5)-(1/2(6+a))=0



Domain of the equation: 4(a+5)!=0

a∈R





Domain of the equation: 2(6+a))!=0

a∈R



We add all the numbers together, and all the variables

1/4(a+5)-(1/2(a+6))=0

We calculate fractions


(2aa/(4(a+5)*2(a+6)))+(-4aa/(4(a+5)*2(a+6)))=0



We calculate terms in parentheses: +(2aa/(4(a+5)*2(a+6))), so:

2aa/(4(a+5)*2(a+6))

We multiply all the terms by the denominator


2aa

Back to the equation:

+(2aa)





We calculate terms in parentheses: +(-4aa/(4(a+5)*2(a+6))), so:

-4aa/(4(a+5)*2(a+6))

We multiply all the terms by the denominator


-4aa

Back to the equation:

+(-4aa)



We get rid of parentheses

2aa-4aa=0

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