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1/4(a+5)=1/5(7-a)
We move all terms to the left:
1/4(a+5)-(1/5(7-a))=0
Domain of the equation: 4(a+5)!=0
a∈R
Domain of the equation: 5(7-a))!=0We add all the numbers together, and all the variables
a∈R
1/4(a+5)-(1/5(-1a+7))=0
We calculate fractions
(5a(-)/(4(a+5)*5(-1a+7)))+(-4aa/(4(a+5)*5(-1a+7)))=0
We calculate terms in parentheses: +(5a(-)/(4(a+5)*5(-1a+7))), so:
5a(-)/(4(a+5)*5(-1a+7))
We add all the numbers together, and all the variables
5a0/(4(a+5)*5(-1a+7))
We multiply all the terms by the denominator
5a0
We add all the numbers together, and all the variables
5a
Back to the equation:
+(5a)
We calculate terms in parentheses: +(-4aa/(4(a+5)*5(-1a+7))), so:We get rid of parentheses
-4aa/(4(a+5)*5(-1a+7))
We multiply all the terms by the denominator
-4aa
Back to the equation:
+(-4aa)
5a-4aa=0
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