1/4(d+2)+6=1/3(2-d)+3

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Solution for 1/4(d+2)+6=1/3(2-d)+3 equation: 



1/4(d+2)+6=1/3(2-d)+3

We move all terms to the left:

1/4(d+2)+6-(1/3(2-d)+3)=0



Domain of the equation: 4(d+2)!=0

d∈R





Domain of the equation: 3(2-d)+3)!=0

d∈R



We add all the numbers together, and all the variables

1/4(d+2)-(1/3(-1d+2)+3)+6=0

We calculate fractions


(3d(-)/(4(d+2)*3(-1d+2))+(-4dd/(4(d+2)*3(-1d+2))+6=0

We can not solve this equation

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