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1/4(j-8)=1/2j+2
We move all terms to the left:
1/4(j-8)-(1/2j+2)=0
Domain of the equation: 4(j-8)!=0
j∈R
Domain of the equation: 2j+2)!=0We get rid of parentheses
j∈R
1/4(j-8)-1/2j-2=0
We calculate fractions
2j/(8j^2-64j)+(-4jj/(8j^2-64j)-2=0
We calculate fractions
We do not support ejpression: j^3
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