1/4(m-12)=3/4m+3

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Solution for 1/4(m-12)=3/4m+3 equation:



1/4(m-12)=3/4m+3
We move all terms to the left:
1/4(m-12)-(3/4m+3)=0
Domain of the equation: 4(m-12)!=0
m∈R
Domain of the equation: 4m+3)!=0
m∈R
We get rid of parentheses
1/4(m-12)-3/4m-3=0
We calculate fractions
4m/(16m^2-192m)+(-12mm/(16m^2-192m)-3=0
We calculate fractions
We do not support empression: m^3

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