1/4(n-6)=1/4n-2/3

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Solution for 1/4(n-6)=1/4n-2/3 equation: 


n in (-oo:+oo)

(1/4)*(n-6) = (1/4)*n-(2/3) // - (1/4)*n-(2/3)

(1/4)*(n-6)-((1/4)*n)+2/3 = 0

(1/4)*(n-6)+(-1/4)*n+2/3 = 0

1/4*(n-6)-n/4+2/3 = 0

(1/4*3*4*(n-6))/(3*4)+(3*(-n))/(3*4)+(2*4)/(3*4) = 0

1/4*3*4*(n-6)+3*(-n)+2*4 = 0

8-18 = 0

-10 = 0

-10/(3*4) = 0

-10/(3*4) = 0 // * 3*4

-10 = 0

n belongs to the empty set

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