1/4(t+5)=1/3(t+3)

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Solution for 1/4(t+5)=1/3(t+3) equation: 



1/4(t+5)=1/3(t+3)

We move all terms to the left:

1/4(t+5)-(1/3(t+3))=0



Domain of the equation: 4(t+5)!=0

t∈R





Domain of the equation: 3(t+3))!=0

t∈R



We calculate fractions


(3tt/(4(t+5)*3(t+3)))+(-4tt/(4(t+5)*3(t+3)))=0



We calculate terms in parentheses: +(3tt/(4(t+5)*3(t+3))), so:

3tt/(4(t+5)*3(t+3))

We multiply all the terms by the denominator


3tt

Back to the equation:

+(3tt)





We calculate terms in parentheses: +(-4tt/(4(t+5)*3(t+3))), so:

-4tt/(4(t+5)*3(t+3))

We multiply all the terms by the denominator


-4tt

Back to the equation:

+(-4tt)



We get rid of parentheses

3tt-4tt=0

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