1/4(t+6)-10=-3t+2

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Solution for 1/4(t+6)-10=-3t+2 equation: 



1/4(t+6)-10=-3t+2

We move all terms to the left:

1/4(t+6)-10-(-3t+2)=0



Domain of the equation: 4(t+6)!=0

t∈R



We get rid of parentheses

1/4(t+6)+3t-2-10=0

We multiply all the terms by the denominator


3t*4(t+6)-2*4(t+6)-10*4(t+6)+1=0

Wy multiply elements

12t^2(t-8t(t-40t(t+1=0

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