1/4(x+1)=3(1-x)+1/2=

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Solution for 1/4(x+1)=3(1-x)+1/2= equation: 



1/4(x+1)=3(1-x)+1/2=

We move all terms to the left:

1/4(x+1)-(3(1-x)+1/2)=0



Domain of the equation: 4(x+1)!=0

x∈R



We add all the numbers together, and all the variables

1/4(x+1)-(3(-1x+1)+1/2)=0

We calculate fractions


()/4x+(-(-3x+4xx)/4x=0

We multiply all the terms by the denominator


(-(-3x+4xx)+()=0



We calculate terms in parentheses: +(-(-3x+4xx)+(), so:

-(-3x+4xx)+(

We add all the numbers together, and all the variables

-(-3x+4xx)

We get rid of parentheses

3x-4xx

Back to the equation:

+(3x-4xx)



We add all the numbers together, and all the variables

(+3x-4xx)=0

We get rid of parentheses

3x-4xx=0

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