1/4(x+12)=10+1/2(4+2x)

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Solution for 1/4(x+12)=10+1/2(4+2x) equation: 



1/4(x+12)=10+1/2(4+2x)

We move all terms to the left:

1/4(x+12)-(10+1/2(4+2x))=0



Domain of the equation: 4(x+12)!=0

x∈R





Domain of the equation: 2(4+2x))!=0

x∈R



We add all the numbers together, and all the variables

1/4(x+12)-(10+1/2(2x+4))=0

We calculate fractions


(2x2/(4(x+12)*2(2x+4)))+(-4xx/(4(x+12)*2(2x+4)))=0



We calculate terms in parentheses: +(2x2/(4(x+12)*2(2x+4))), so:

2x2/(4(x+12)*2(2x+4))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)





We calculate terms in parentheses: +(-4xx/(4(x+12)*2(2x+4))), so:

-4xx/(4(x+12)*2(2x+4))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)



We get rid of parentheses

2x^2-4xx=0

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