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1/4(x+2)=1/3(x+4)
We move all terms to the left:
1/4(x+2)-(1/3(x+4))=0
Domain of the equation: 4(x+2)!=0
x∈R
Domain of the equation: 3(x+4))!=0We calculate fractions
x∈R
(3xx/(4(x+2)*3(x+4)))+(-4xx/(4(x+2)*3(x+4)))=0
We calculate terms in parentheses: +(3xx/(4(x+2)*3(x+4))), so:
3xx/(4(x+2)*3(x+4))
We multiply all the terms by the denominator
3xx
Back to the equation:
+(3xx)
We calculate terms in parentheses: +(-4xx/(4(x+2)*3(x+4))), so:We get rid of parentheses
-4xx/(4(x+2)*3(x+4))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
3xx-4xx=0
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