1/4(x+2)=1/6(5-x)

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Solution for 1/4(x+2)=1/6(5-x) equation: 



1/4(x+2)=1/6(5-x)

We move all terms to the left:

1/4(x+2)-(1/6(5-x))=0



Domain of the equation: 4(x+2)!=0

x∈R





Domain of the equation: 6(5-x))!=0

x∈R



We add all the numbers together, and all the variables

1/4(x+2)-(1/6(-1x+5))=0

We calculate fractions


(6x(-)/(4(x+2)*6(-1x+5)))+(-4xx/(4(x+2)*6(-1x+5)))=0



We calculate terms in parentheses: +(6x(-)/(4(x+2)*6(-1x+5))), so:

6x(-)/(4(x+2)*6(-1x+5))

We add all the numbers together, and all the variables

6x0/(4(x+2)*6(-1x+5))

We multiply all the terms by the denominator


6x0

We add all the numbers together, and all the variables

6x

Back to the equation:

+(6x)





We calculate terms in parentheses: +(-4xx/(4(x+2)*6(-1x+5))), so:

-4xx/(4(x+2)*6(-1x+5))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)



We get rid of parentheses

6x-4xx=0

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