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1/4(x+2)=3/4(x+2)
We move all terms to the left:
1/4(x+2)-(3/4(x+2))=0
Domain of the equation: 4(x+2)!=0
x∈R
Domain of the equation: 4(x+2))!=0We calculate fractions
x∈R
(4xx/(4(x+2)*4(x+2)))+(-12xx/(4(x+2)*4(x+2)))=0
We calculate terms in parentheses: +(4xx/(4(x+2)*4(x+2))), so:
4xx/(4(x+2)*4(x+2))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-12xx/(4(x+2)*4(x+2))), so:We get rid of parentheses
-12xx/(4(x+2)*4(x+2))
We multiply all the terms by the denominator
-12xx
Back to the equation:
+(-12xx)
4xx-12xx=0
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