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x in (-oo:+oo)
(1/4)*(x+4) = (1/12)*(3*x+12) // - (1/12)*(3*x+12)
(1/4)*(x+4)-((1/12)*(3*x+12)) = 0
(1/4)*(x+4)+(-1/12)*(3*x+12) = 0
1/4*(x+4)-1/12*(3*x+12) = 0
1/4*(x+4)-1/12*(3*x+12) = 0
0 = 0
0 = 0
x belongs to the empty set
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