1/4(x+4)=1/12(3x+12)

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Solution for 1/4(x+4)=1/12(3x+12) equation:


x in (-oo:+oo)

(1/4)*(x+4) = (1/12)*(3*x+12) // - (1/12)*(3*x+12)

(1/4)*(x+4)-((1/12)*(3*x+12)) = 0

(1/4)*(x+4)+(-1/12)*(3*x+12) = 0

1/4*(x+4)-1/12*(3*x+12) = 0

1/4*(x+4)-1/12*(3*x+12) = 0

0 = 0

0 = 0

x belongs to the empty set

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