1/4(x+4)=1/5(2x+6)

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Solution for 1/4(x+4)=1/5(2x+6) equation:



1/4(x+4)=1/5(2x+6)
We move all terms to the left:
1/4(x+4)-(1/5(2x+6))=0
Domain of the equation: 4(x+4)!=0
x∈R
Domain of the equation: 5(2x+6))!=0
x∈R
We calculate fractions
(5x2/(4(x+4)*5(2x+6)))+(-4xx/(4(x+4)*5(2x+6)))=0
We calculate terms in parentheses: +(5x2/(4(x+4)*5(2x+6))), so:
5x2/(4(x+4)*5(2x+6))
We multiply all the terms by the denominator
5x2
We add all the numbers together, and all the variables
5x^2
Back to the equation:
+(5x^2)
We calculate terms in parentheses: +(-4xx/(4(x+4)*5(2x+6))), so:
-4xx/(4(x+4)*5(2x+6))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
We get rid of parentheses
5x^2-4xx=0

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