1/4(x+4)=1/7(3x+5)

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Solution for 1/4(x+4)=1/7(3x+5) equation: 



1/4(x+4)=1/7(3x+5)

We move all terms to the left:

1/4(x+4)-(1/7(3x+5))=0



Domain of the equation: 4(x+4)!=0

x∈R





Domain of the equation: 7(3x+5))!=0

x∈R



We calculate fractions


(7x3/(4(x+4)*7(3x+5)))+(-4xx/(4(x+4)*7(3x+5)))=0



We calculate terms in parentheses: +(7x3/(4(x+4)*7(3x+5))), so:

7x3/(4(x+4)*7(3x+5))

We multiply all the terms by the denominator


7x3

We add all the numbers together, and all the variables

7x^3

We do not support expression: x^3

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