1/4(x+8)=3/4(x+12)

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Solution for 1/4(x+8)=3/4(x+12) equation: 



1/4(x+8)=3/4(x+12)

We move all terms to the left:

1/4(x+8)-(3/4(x+12))=0



Domain of the equation: 4(x+8)!=0

x∈R





Domain of the equation: 4(x+12))!=0

x∈R



We calculate fractions


(4xx/(4(x+8)*4(x+12)))+(-12xx/(4(x+8)*4(x+12)))=0



We calculate terms in parentheses: +(4xx/(4(x+8)*4(x+12))), so:

4xx/(4(x+8)*4(x+12))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-12xx/(4(x+8)*4(x+12))), so:

-12xx/(4(x+8)*4(x+12))

We multiply all the terms by the denominator


-12xx

Back to the equation:

+(-12xx)



We get rid of parentheses

4xx-12xx=0

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