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1/4(x-12)=1/4x-9+6
We move all terms to the left:
1/4(x-12)-(1/4x-9+6)=0
Domain of the equation: 4(x-12)!=0
x∈R
Domain of the equation: 4x-9+6)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
4x+6)!=9
x∈R
1/4(x-12)-(1/4x-3)=0
We get rid of parentheses
1/4(x-12)-1/4x+3=0
We calculate fractions
4x/(16x^2-192x)+(-4xx/(16x^2-192x)+3=0
We calculate fractions
We do not support expression: x^3
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