1/4(x-2)+1/2(3x-1)=1/8(x+1)

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Solution for 1/4(x-2)+1/2(3x-1)=1/8(x+1) equation: 


x in (-oo:+oo)

(1/4)*(x-2)+(1/2)*(3*x-1) = (1/8)*(x+1) // - (1/8)*(x+1)

(1/4)*(x-2)+(1/2)*(3*x-1)-((1/8)*(x+1)) = 0

(1/4)*(x-2)+(1/2)*(3*x-1)+(-1/8)*(x+1) = 0

1/4*(x-2)+1/2*(3*x-1)-1/8*(x+1) = 0

1/4*(x-2)+1/2*(3*x-1)-1/8*(x+1) = 0

7/4*x-1/8*x-1-1/8 = 0

13/8*x-9/8 = 0

13/8*x-9/8 = 0

13/8*x-9/8 = 0 // + 9/8

13/8*x = 9/8 // : 13/8

x = 9/8/13/8

x = 9/13

x = 9/13

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