1/4(x-2)+1/3=x-1/3(2x-1)

Solution for 1/4(x-2)+1/3=x-1/3(2x-1) equation:

1/4(x-2)+1/3=x-1/3(2x-1)

We move all terms to the left:

1/4(x-2)+1/3-(x-1/3(2x-1))=0


Domain of the equation: 4(x-2)!=0

x∈R



Domain of the equation: 3(2x-1))!=0

x∈R


We calculate fractions


(9x2/(4(x-2)*3(2x-1))*3)+(-(x-4xx)/(4(x-2)*3(2x-1))*3)+(4xx/(4(x-2)*3(2x-1))*3)=0


We calculate terms in parentheses: +(9x2/(4(x-2)*3(2x-1))*3), so:

9x2/(4(x-2)*3(2x-1))*3

We multiply all the terms by the denominator


9x2

We add all the numbers together, and all the variables

9x^2

Back to the equation:

+(9x^2)



We calculate terms in parentheses: +(-(x-4xx)/(4(x-2)*3(2x-1))*3), so:

-(x-4xx)/(4(x-2)*3(2x-1))*3

We add all the numbers together, and all the variables

-(+x-4xx)/(4(x-2)*3(2x-1))*3

We multiply all the terms by the denominator


-(+x-4xx)

We get rid of parentheses

-x+4xx

We add all the numbers together, and all the variables

-1x+4xx

Back to the equation:

+(-1x+4xx)



We calculate terms in parentheses: +(4xx/(4(x-2)*3(2x-1))*3), so:

4xx/(4(x-2)*3(2x-1))*3

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)


We get rid of parentheses

9x^2-1x+4xx+4xx=0