1/4(x-3)=1/6(x+5)

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Solution for 1/4(x-3)=1/6(x+5) equation:



1/4(x-3)=1/6(x+5)
We move all terms to the left:
1/4(x-3)-(1/6(x+5))=0
Domain of the equation: 4(x-3)!=0
x∈R
Domain of the equation: 6(x+5))!=0
x∈R
We calculate fractions
(6xx/(4(x-3)*6(x+5)))+(-4xx/(4(x-3)*6(x+5)))=0
We calculate terms in parentheses: +(6xx/(4(x-3)*6(x+5))), so:
6xx/(4(x-3)*6(x+5))
We multiply all the terms by the denominator
6xx
Back to the equation:
+(6xx)
We calculate terms in parentheses: +(-4xx/(4(x-3)*6(x+5))), so:
-4xx/(4(x-3)*6(x+5))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
We get rid of parentheses
6xx-4xx=0

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