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1/4(x-3)=2/3(x+2)
We move all terms to the left:
1/4(x-3)-(2/3(x+2))=0
Domain of the equation: 4(x-3)!=0
x∈R
Domain of the equation: 3(x+2))!=0We calculate fractions
x∈R
(3xx/(4(x-3)*3(x+2)))+(-8xx/(4(x-3)*3(x+2)))=0
We calculate terms in parentheses: +(3xx/(4(x-3)*3(x+2))), so:
3xx/(4(x-3)*3(x+2))
We multiply all the terms by the denominator
3xx
Back to the equation:
+(3xx)
We calculate terms in parentheses: +(-8xx/(4(x-3)*3(x+2))), so:We get rid of parentheses
-8xx/(4(x-3)*3(x+2))
We multiply all the terms by the denominator
-8xx
Back to the equation:
+(-8xx)
3xx-8xx=0
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