1/4(x-8)=1/5(2x-1)

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Solution for 1/4(x-8)=1/5(2x-1) equation: 



1/4(x-8)=1/5(2x-1)

We move all terms to the left:

1/4(x-8)-(1/5(2x-1))=0



Domain of the equation: 4(x-8)!=0

x∈R





Domain of the equation: 5(2x-1))!=0

x∈R



We calculate fractions


(5x2/(4(x-8)*5(2x-1)))+(-4xx/(4(x-8)*5(2x-1)))=0



We calculate terms in parentheses: +(5x2/(4(x-8)*5(2x-1))), so:

5x2/(4(x-8)*5(2x-1))

We multiply all the terms by the denominator


5x2

We add all the numbers together, and all the variables

5x^2

Back to the equation:

+(5x^2)





We calculate terms in parentheses: +(-4xx/(4(x-8)*5(2x-1))), so:

-4xx/(4(x-8)*5(2x-1))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)



We get rid of parentheses

5x^2-4xx=0

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