1/4(y+2)+5=1/3(4y-1)-18

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Solution for 1/4(y+2)+5=1/3(4y-1)-18 equation: 



1/4(y+2)+5=1/3(4y-1)-18

We move all terms to the left:

1/4(y+2)+5-(1/3(4y-1)-18)=0



Domain of the equation: 4(y+2)!=0

y∈R





Domain of the equation: 3(4y-1)-18)!=0

y∈R



We calculate fractions


(3y4/(4(y+2)*3(4y-1))+(-4yy/(4(y+2)*3(4y-1))+5=0

We can not solve this equation

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