1/4(y+2)=y-7

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Solution for 1/4(y+2)=y-7 equation: 



1/4(y+2)=y-7

We move all terms to the left:

1/4(y+2)-(y-7)=0



Domain of the equation: 4(y+2)!=0

y∈R



We get rid of parentheses

1/4(y+2)-y+7=0

We multiply all the terms by the denominator


-y*4(y+2)+7*4(y+2)+1=0

Wy multiply elements

-4y^2(y+28y(y+1=0

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