1/4(y+5)+7=1/3(4y-1)-12

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Solution for 1/4(y+5)+7=1/3(4y-1)-12 equation: 



1/4(y+5)+7=1/3(4y-1)-12

We move all terms to the left:

1/4(y+5)+7-(1/3(4y-1)-12)=0



Domain of the equation: 4(y+5)!=0

y∈R





Domain of the equation: 3(4y-1)-12)!=0

y∈R



We calculate fractions


(3y4/(4(y+5)*3(4y-1))+(-4yy/(4(y+5)*3(4y-1))+7=0

We can not solve this equation

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