1/4(y+5)=1/3(y+3)

Solution for 1/4(y+5)=1/3(y+3) equation:

1/4(y+5)=1/3(y+3)

We move all terms to the left:

1/4(y+5)-(1/3(y+3))=0


Domain of the equation: 4(y+5)!=0

y∈R



Domain of the equation: 3(y+3))!=0

y∈R


We calculate fractions


(3yy/(4(y+5)*3(y+3)))+(-4yy/(4(y+5)*3(y+3)))=0


We calculate terms in parentheses: +(3yy/(4(y+5)*3(y+3))), so:

3yy/(4(y+5)*3(y+3))

We multiply all the terms by the denominator


3yy

Back to the equation:

+(3yy)



We calculate terms in parentheses: +(-4yy/(4(y+5)*3(y+3))), so:

-4yy/(4(y+5)*3(y+3))

We multiply all the terms by the denominator


-4yy

Back to the equation:

+(-4yy)


We get rid of parentheses

3yy-4yy=0