1/4(y+8)+6=1/3(4y-1)-9

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Solution for 1/4(y+8)+6=1/3(4y-1)-9 equation:



1/4(y+8)+6=1/3(4y-1)-9
We move all terms to the left:
1/4(y+8)+6-(1/3(4y-1)-9)=0
Domain of the equation: 4(y+8)!=0
y∈R
Domain of the equation: 3(4y-1)-9)!=0
y∈R
We calculate fractions
(3y4/(4(y+8)*3(4y-1))+(-4yy/(4(y+8)*3(4y-1))+6=0
We can not solve this equation

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