1/4(y-16)=1/2y

Solution for 1/4(y-16)=1/2y equation:

1/4(y-16)=1/2y

We move all terms to the left:

1/4(y-16)-(1/2y)=0


Domain of the equation: 4(y-16)!=0

y∈R



Domain of the equation: 2y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

1/4(y-16)-(+1/2y)=0

We get rid of parentheses

1/4(y-16)-1/2y=0

We calculate fractions


2y/(8y^2-128y)+(-4yy/(8y^2-128y)=0


We calculate terms in parentheses: +(-4yy/(8y^2-128y), so:

-4yy/(8y^2-128y

We multiply all the terms by the denominator


-4yy

Back to the equation:

+(-4yy)


We get rid of parentheses

2y/(8y^2-128y)-4yy=0

We multiply all the terms by the denominator


2y-4yy*(8y^2-128y)=0

We multiply parentheses

-32y^3+512y^2+2y=0

We do not support eypression: y^3