1/4(y-2)=1/2(y+1)

Solution for 1/4(y-2)=1/2(y+1) equation:

1/4(y-2)=1/2(y+1)

We move all terms to the left:

1/4(y-2)-(1/2(y+1))=0


Domain of the equation: 4(y-2)!=0

y∈R



Domain of the equation: 2(y+1))!=0

y∈R


We calculate fractions


(2yy/(4(y-2)*2(y+1)))+(-4yy/(4(y-2)*2(y+1)))=0


We calculate terms in parentheses: +(2yy/(4(y-2)*2(y+1))), so:

2yy/(4(y-2)*2(y+1))

We multiply all the terms by the denominator


2yy

Back to the equation:

+(2yy)



We calculate terms in parentheses: +(-4yy/(4(y-2)*2(y+1))), so:

-4yy/(4(y-2)*2(y+1))

We multiply all the terms by the denominator


-4yy

Back to the equation:

+(-4yy)


We get rid of parentheses

2yy-4yy=0