1/4(y-3)+10=11/12(5y-23)

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Solution for 1/4(y-3)+10=11/12(5y-23) equation: 



1/4(y-3)+10=11/12(5y-23)

We move all terms to the left:

1/4(y-3)+10-(11/12(5y-23))=0



Domain of the equation: 4(y-3)!=0

y∈R





Domain of the equation: 12(5y-23))!=0

y∈R



We calculate fractions


(12y5/(4(y-3)*12(5y-23)))+(-44yy/(4(y-3)*12(5y-23)))+10=0



We calculate terms in parentheses: +(12y5/(4(y-3)*12(5y-23))), so:

12y5/(4(y-3)*12(5y-23))

We multiply all the terms by the denominator


12y5

We add all the numbers together, and all the variables

12y^5

We do not support eypression: y^5

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