1/4(y-5)=2/7(14-3y)

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Solution for 1/4(y-5)=2/7(14-3y) equation: 



1/4(y-5)=2/7(14-3y)

We move all terms to the left:

1/4(y-5)-(2/7(14-3y))=0



Domain of the equation: 4(y-5)!=0

y∈R





Domain of the equation: 7(14-3y))!=0

y∈R



We add all the numbers together, and all the variables

1/4(y-5)-(2/7(-3y+14))=0

We calculate fractions


(7y(-)/(4(y-5)*7(-3y+14)))+(-8yy/(4(y-5)*7(-3y+14)))=0



We calculate terms in parentheses: +(7y(-)/(4(y-5)*7(-3y+14))), so:

7y(-)/(4(y-5)*7(-3y+14))

We add all the numbers together, and all the variables

7y0/(4(y-5)*7(-3y+14))

We multiply all the terms by the denominator


7y0

We add all the numbers together, and all the variables

7y

Back to the equation:

+(7y)





We calculate terms in parentheses: +(-8yy/(4(y-5)*7(-3y+14))), so:

-8yy/(4(y-5)*7(-3y+14))

We multiply all the terms by the denominator


-8yy

Back to the equation:

+(-8yy)



We get rid of parentheses

7y-8yy=0

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