1/4(z+3z)+7=-z+1

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Solution for 1/4(z+3z)+7=-z+1 equation: 



1/4(z+3z)+7=-z+1

We move all terms to the left:

1/4(z+3z)+7-(-z+1)=0



Domain of the equation: 4(z+3z)!=0

z∈R



We add all the numbers together, and all the variables

1/4(+4z)-(-1z+1)+7=0

We get rid of parentheses

1/4(+4z)+1z-1+7=0

We multiply all the terms by the denominator


1z*4(+4z)-1*4(+4z)+7*4(+4z)+1=0

Wy multiply elements

4z^2(+-4z(++28z(++1=0

We use the square of the difference formula

4z^2(-4z(+28z(+1=0

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