1/4(z-4)=7/6z+1/10Z+1

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Solution for 1/4(z-4)=7/6z+1/10Z+1 equation: 


x in (-oo:+oo)

(1/4)*(z-4) = (1/10)*Z+(7/6)*z+1 // - (1/10)*Z+(7/6)*z+1

(1/4)*(z-4)-((1/10)*Z)-((7/6)*z)-1 = 0

(1/4)*(z-4)+(-1/10)*Z+(-7/6)*z-1 = 0

1/4*(z-4)-Z/10+(-7*z)/6-1 = 0

(1/4*6*10*(z-4))/(6*10)+(6*(-Z))/(6*10)+(-7*10*z)/(6*10)+(-1*6*10)/(6*10) = 0

1/4*6*10*(z-4)+6*(-Z)-7*10*z-1*6*10 = 0

15*z-6*Z-70*z-60-60 = 0

-6*Z-55*z-60-60 = 0

-6*Z-55*z-120 = 0

(-6*Z-55*z-120)/(6*10) = 0

(-6*Z-55*z-120)/(6*10) = 0 // * 6*10

-6*Z-55*z-120 = 0

x belongs to the empty set

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