1/4(z-6)=1/4z-3/2

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Solution for 1/4(z-6)=1/4z-3/2 equation:


z in (-oo:+oo)

(1/4)*(z-6) = (1/4)*z-(3/2) // - (1/4)*z-(3/2)

(1/4)*(z-6)-((1/4)*z)+3/2 = 0

(1/4)*(z-6)+(-1/4)*z+3/2 = 0

1/4*(z-6)-z/4+3/2 = 0

(1/4*2*4*(z-6))/(2*4)+(2*(-z))/(2*4)+(3*4)/(2*4) = 0

1/4*2*4*(z-6)+2*(-z)+3*4 = 0

12-12 = 0

0 = 0

0/(2*4) = 0

0/(2*4) = 0 // * 2*4

0 = 0

z belongs to the empty set

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