1/4*(9-2x)=1/8*(3x+4)

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Solution for 1/4*(9-2x)=1/8*(3x+4) equation: 



1/4(9-2x)=1/8(3x+4)

We move all terms to the left:

1/4(9-2x)-(1/8(3x+4))=0



Domain of the equation: 4(9-2x)!=0

x∈R





Domain of the equation: 8(3x+4))!=0

x∈R



We add all the numbers together, and all the variables

1/4(-2x+9)-(1/8(3x+4))=0

We calculate fractions


(8x3/(4(-2x+9)*8(3x+4)))+(-4x0/(4(-2x+9)*8(3x+4)))=0



We calculate terms in parentheses: +(8x3/(4(-2x+9)*8(3x+4))), so:

8x3/(4(-2x+9)*8(3x+4))

We multiply all the terms by the denominator


8x3

We add all the numbers together, and all the variables

8x^3

We do not support expression: x^3

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