1/40(2z-4)=4z+6

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Solution for 1/40(2z-4)=4z+6 equation: 



1/40(2z-4)=4z+6

We move all terms to the left:

1/40(2z-4)-(4z+6)=0



Domain of the equation: 40(2z-4)!=0

z∈R



We get rid of parentheses

1/40(2z-4)-4z-6=0

We multiply all the terms by the denominator


-4z*40(2z-4)-6*40(2z-4)+1=0

Wy multiply elements

-160z^2(2-240z(2+1=0

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