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1/4X-1/8X=2/3
We move all terms to the left:
1/4X-1/8X-(2/3)=0
Domain of the equation: 4X!=0
X!=0/4
X!=0
X∈R
Domain of the equation: 8X!=0We add all the numbers together, and all the variables
X!=0/8
X!=0
X∈R
1/4X-1/8X-(+2/3)=0
We get rid of parentheses
1/4X-1/8X-2/3=0
We calculate fractions
(-512X^2)/288X^2+72X/288X^2+(-36X)/288X^2=0
We multiply all the terms by the denominator
(-512X^2)+72X+(-36X)=0
We get rid of parentheses
-512X^2+72X-36X=0
We add all the numbers together, and all the variables
-512X^2+36X=0
a = -512; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-512)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-512}=\frac{-72}{-1024} =9/128 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-512}=\frac{0}{-1024} =0 $
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