1/4b+10=2

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Solution for 1/4b+10=2 equation: 



1/4b+10=2

We move all terms to the left:

1/4b+10-(2)=0



Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R



We add all the numbers together, and all the variables

1/4b+8=0

We multiply all the terms by the denominator


8*4b+1=0

Wy multiply elements

32b+1=0

We move all terms containing b to the left, all other terms to the right

32b=-1

b=-1/32

b=-1/32

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