1/4b+10=2

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Solution for 1/4b+10=2 equation:



1/4b+10=2
We move all terms to the left:
1/4b+10-(2)=0
Domain of the equation: 4b!=0
b!=0/4
b!=0
b∈R
We add all the numbers together, and all the variables
1/4b+8=0
We multiply all the terms by the denominator
8*4b+1=0
Wy multiply elements
32b+1=0
We move all terms containing b to the left, all other terms to the right
32b=-1
b=-1/32
b=-1/32

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