1/4b-1/2b=1/2-3

Solution for 1/4b-1/2b=1/2-3 equation:

1/4b-1/2b=1/2-3

We move all terms to the left:

1/4b-1/2b-(1/2-3)=0


Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We get rid of parentheses

1/4b-1/2b+3-1/2=0

We calculate fractions


8b/32b^2+(-4b)/32b^2+(-4b)/32b^2+3=0

We multiply all the terms by the denominator


8b+(-4b)+(-4b)+3*32b^2=0

Wy multiply elements

96b^2+8b+(-4b)+(-4b)=0

We get rid of parentheses

96b^2+8b-4b-4b=0

We add all the numbers together, and all the variables

96b^2=0

a = 96; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·96·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{192}=0$