1/4d+3=1/3d+1

Solution for 1/4d+3=1/3d+1 equation:

1/4d+3=1/3d+1

We move all terms to the left:

1/4d+3-(1/3d+1)=0


Domain of the equation: 4d!=0

d!=0/4

d!=0

d∈R



Domain of the equation: 3d+1)!=0

d∈R


We get rid of parentheses

1/4d-1/3d-1+3=0

We calculate fractions


3d/12d^2+(-4d)/12d^2-1+3=0

We add all the numbers together, and all the variables

3d/12d^2+(-4d)/12d^2+2=0

We multiply all the terms by the denominator


3d+(-4d)+2*12d^2=0

Wy multiply elements

24d^2+3d+(-4d)=0

We get rid of parentheses

24d^2+3d-4d=0

We add all the numbers together, and all the variables

24d^2-1d=0

a = 24; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·24·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*24}=\frac{0}{48}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*24}=\frac{2}{48}
=1/24
$