1/4h+1/2h+4=8

Solution for 1/4h+1/2h+4=8 equation:

1/4h+1/2h+4=8

We move all terms to the left:

1/4h+1/2h+4-(8)=0


Domain of the equation: 4h!=0

h!=0/4

h!=0

h∈R



Domain of the equation: 2h!=0

h!=0/2

h!=0

h∈R


We add all the numbers together, and all the variables

1/4h+1/2h-4=0

We calculate fractions


2h/8h^2+4h/8h^2-4=0

We multiply all the terms by the denominator


2h+4h-4*8h^2=0

We add all the numbers together, and all the variables

6h-4*8h^2=0

Wy multiply elements

-32h^2+6h=0

a = -32; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-32)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-32}=\frac{-12}{-64}
=3/16
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-32}=\frac{0}{-64}
=0
$