1/4k-(k+1/2)=1/8(k+1)

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Solution for 1/4k-(k+1/2)=1/8(k+1) equation: 


k in (-oo:+oo)

(1/4)*k-k-(1/2) = (1/8)*(k+1) // - (1/8)*(k+1)

(1/4)*k-((1/8)*(k+1))-k-(1/2) = 0

(-1/8)*(k+1)+(1/4)*k-k-1/2 = 0

k/4-1/8*(k+1)-k-1/2 = 0

(-1/8*2*4*(k+1))/(2*4)+(2*k)/(2*4)+(2*4*(-k))/(2*4)+(-1*4)/(2*4) = 0

2*k-1/8*2*4*(k+1)+2*4*(-k)-1*4 = 0

k-8*k-4-1 = 0

-7*k-4-1 = 0

-7*k-5 = 0

(-7*k-5)/(2*4) = 0

(-7*k-5)/(2*4) = 0 // * 2*4

-7*k-5 = 0

-7*k-5 = 0 // + 5

-7*k = 5 // : -7

k = 5/(-7)

k = -5/7

k = -5/7

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