1/4k-(k+1/2)=1/8(k+4)

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Solution for 1/4k-(k+1/2)=1/8(k+4) equation: 


k in (-oo:+oo)

(1/4)*k-k-(1/2) = (1/8)*(k+4) // - (1/8)*(k+4)

(1/4)*k-((1/8)*(k+4))-k-(1/2) = 0

(-1/8)*(k+4)+(1/4)*k-k-1/2 = 0

k/4-1/8*(k+4)-k-1/2 = 0

(-1/8*2*4*(k+4))/(2*4)+(2*k)/(2*4)+(2*4*(-k))/(2*4)+(-1*4)/(2*4) = 0

2*k-1/8*2*4*(k+4)+2*4*(-k)-1*4 = 0

k-8*k-4-4 = 0

-7*k-4-4 = 0

-7*k-8 = 0

(-7*k-8)/(2*4) = 0

(-7*k-8)/(2*4) = 0 // * 2*4

-7*k-8 = 0

-7*k-8 = 0 // + 8

-7*k = 8 // : -7

k = 8/(-7)

k = -8/7

k = -8/7

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