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1/4p+4=1/3p
We move all terms to the left:
1/4p+4-(1/3p)=0
Domain of the equation: 4p!=0
p!=0/4
p!=0
p∈R
Domain of the equation: 3p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
1/4p-(+1/3p)+4=0
We get rid of parentheses
1/4p-1/3p+4=0
We calculate fractions
3p/12p^2+(-4p)/12p^2+4=0
We multiply all the terms by the denominator
3p+(-4p)+4*12p^2=0
Wy multiply elements
48p^2+3p+(-4p)=0
We get rid of parentheses
48p^2+3p-4p=0
We add all the numbers together, and all the variables
48p^2-1p=0
a = 48; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·48·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*48}=\frac{0}{96} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*48}=\frac{2}{96} =1/48 $
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