1/4t+4=3/4(t=8)

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Solution for 1/4t+4=3/4(t=8) equation: 



1/4t+4=3/4(t=8)

We move all terms to the left:

1/4t+4-(3/4(t)=0



Domain of the equation: 4t!=0

t!=0/4

t!=0

t∈R





Domain of the equation: 4t+4!=0

We move all terms containing t to the left, all other terms to the right

4t!=-4

t!=-4/4

t!=-1

t∈R



We calculate fractions


(4t+4)/(16t^2+4)+(-(3*4t)/(16t^2+4)=0



We calculate terms in parentheses: +(-(3*4t)/(16t^2+4), so:

-(3*4t)/(16t^2+4

We add all the numbers together, and all the variables

-(+3*4t)/(16t^2+4

We multiply all the terms by the denominator


-(+3*4t)

We get rid of parentheses

-3*4t

Wy multiply elements

-12t

Back to the equation:

+(-12t)



We get rid of parentheses

(4t+4)/(16t^2+4)-12t=0

We multiply all the terms by the denominator


(4t+4)-12t*(16t^2+4)=0

We multiply parentheses

-192t^3+(4t+4)-48t=0

We get rid of parentheses

-192t^3+4t-48t+4=0

We do not support etpression: t^3

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