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1/4v-1=1/v
We move all terms to the left:
1/4v-1-(1/v)=0
Domain of the equation: 4v!=0
v!=0/4
v!=0
v∈R
Domain of the equation: v)!=0We add all the numbers together, and all the variables
v!=0/1
v!=0
v∈R
1/4v-(+1/v)-1=0
We get rid of parentheses
1/4v-1/v-1=0
We calculate fractions
v/4v^2+(-4v)/4v^2-1=0
We multiply all the terms by the denominator
v+(-4v)-1*4v^2=0
Wy multiply elements
-4v^2+v+(-4v)=0
We get rid of parentheses
-4v^2+v-4v=0
We add all the numbers together, and all the variables
-4v^2-3v=0
a = -4; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-4)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-4}=\frac{0}{-8} =0 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-4}=\frac{6}{-8} =-3/4 $
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